The secret of the birth of Alla Pugacheva’s children has become known.
'01.10.2018'
Source: 7 Days
As you know, officially Alla Pugacheva is the mother of three children: Christina Orbakaite and the twins Lisa and Harry. However, recently it became known that, perhaps, the Prima Donna may have other children. The ex-wife of Vladimir Kuzmin told about this.
Tatiana, the ex-wife of the singer, said: many years ago, Alla Borisovna was Kuzmin’s mistress, 7 Days. Moreover, she allegedly was three times pregnant by the artist, says the woman. According to the former wife of the musician, the Prima Donna carried out all three children and sent them to orphanages. According to Tatyana, a girl born to Pugacheva from Kuzmin grew up in a shelter on the Black Sea coast.
“She had not one pregnancy from Kuzmin, but three. She gave birth to everyone, ”Tatiana said in the DNA program on NTV. According to the former wife of the singer, all three times Alla Borisovna carefully concealed her pregnancy from others. However, in 1987, at the song contest in San Remo, Diva failed to hide her “position”, which was not difficult to guess from her rounded belly.
The prima donna has not yet responded to Tatiana's revelations and probably will not do that. After all, the words of the former wife Kuzmin sound a little crazy. Even before Liza and Harry appeared, Pugacheva said that she had dreamed of having another child besides Christina for many years, but she could not get pregnant.
According to rumors, in 90's, the actress even resorted to IVF in order to give birth to a daughter of a brother or sister. TV viewers suggest that Tatiana decided on the allegedly sensational recognition for the fee for participation in the show.
